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9x^2-25x-4=0
a = 9; b = -25; c = -4;
Δ = b2-4ac
Δ = -252-4·9·(-4)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{769}}{2*9}=\frac{25-\sqrt{769}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{769}}{2*9}=\frac{25+\sqrt{769}}{18} $
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